Upgrading to a powerful system (1500+ watts)

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I can do 2 3" flared ports and get 4 cubes. The 3" flared ports have a diameter of 6.25" at the flare, so that's 30.68 sq. inches of port per tube.... so 61.35 sq. inches of port... divided by 4 cubes gives me 15.34 sq. inches of port per cube. That's perfect. And if I did my math right two 3" flared ports take up around .23 cubes if they're 8" long.

 

But back to the point at hand... would you do 4 cubes @33Hz over 3.25 cubes @33Hz?

 

I'm going to put 1000-1100 watts to it. I didn't realize the port area was the same even though it was flared... back to the drawing board.

 

I took my two 400.1's and subs out.







Okay. As of right now the new box's outer dimensions will be 39" wide, 14" deep, and 21" tall. The box in the picture is 39" wide, 14" deep, and 14" tall... so basically picture that box but 7" taller.

I'm going to stand the spare tire up behind the box. My old setup was very impractical and had I ever gotten a flat I would have had a spare and no way to get it without another person to help me get the box out.

Like I said, the depth of the new box will be the same, does that look like sufficient space in between the sub and the back wall?

 

(21" tall)

3.75 cubes @33Hz... port is 2.5"x19.5"x25" long... I have .13 cubes left over I need to fill with bracing. How do you guys think I should brace it?

 

Okay if I use threaded rods I can do 3.9 cubes @ 33Hz.

 

A guy on termpro said I don't need the double baffle. What do you think?

 

What do you think?

 

Well as you can see, I'm at 3.9916 cubes right now, so if I did MDF instead of the threaded rods, I'd have to eliminate the 2x4's. I had planned on just having the bolts showing, I thought it might look cool with an industrial sort of look... but that's an idea cutting holes in the outer baffle and having the nuts recessed.